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erc-c/src/mos6502.dis.c

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/*
* mos6502.dis.c
*
* Disassembly of the mos6502 machine code into an assembly notation.
*/
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#include <stdbool.h>
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#include "mos6502.h"
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#include "mos6502.dis.h"
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#include "mos6502.enums.h"
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static vm_8bit jump_table[MOS6502_MEMSIZE];
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static char *instruction_strings[] = {
"ADC",
"AND",
"ASL",
"BCC",
"BCS",
"BEQ",
"BIT",
"BMI",
"BNE",
"BPL",
"BRK",
"BVC",
"BVS",
"CLC",
"CLD",
"CLI",
"CLV",
"CMP",
"CPX",
"CPY",
"DEC",
"DEX",
"DEY",
"EOR",
"INC",
"INX",
"INY",
"JMP",
"JSR",
"LDA",
"LDX",
"LDY",
"LSR",
"NOP",
"ORA",
"PHA",
"PHP",
"PLA",
"PLP",
"ROL",
"ROR",
"RTI",
"RTS",
"SBC",
"SEC",
"SED",
"SEI",
"STA",
"STX",
"STY",
"TAX",
"TAY",
"TSX",
"TXA",
"TXS",
"TYA",
};
/*
* Given a stream, address mode and 16-bit value, print the value out in
* the form that is expected given the address mode. The value is not
* necessarily going to truly be 16-bit; most address modes use one
* 8-bit operand. But we can contain all possible values with the 16-bit
* type.
*/
void
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mos6502_dis_operand(FILE *stream, int address, int addr_mode, vm_16bit value)
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{
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int rel_address;
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switch (addr_mode) {
case ACC:
break;
case ABS:
fprintf(stream, "$%04X", value);
break;
case ABX:
fprintf(stream, "$%04X,X", value);
break;
case ABY:
fprintf(stream, "$%04X,Y", value);
break;
case IMM:
fprintf(stream, "#$%02X", value);
break;
case IMP:
break;
case IND:
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if (jump_table[value]) {
mos6502_dis_label(stream, value);
} else {
fprintf(stream, "($%04X)", value);
}
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break;
case IDX:
fprintf(stream, "($%02X,X)", value);
break;
case IDY:
fprintf(stream, "($%02X),Y", value);
break;
case REL:
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rel_address = address + value;
if (value > 127) {
rel_address -= 256;
}
mos6502_dis_label(stream, rel_address);
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break;
case ZPG:
fprintf(stream, "$%02X", value);
break;
case ZPX:
fprintf(stream, "$%02X,X", value);
break;
case ZPY:
fprintf(stream, "$%02X,Y", value);
break;
}
}
/*
* This function will write to the stream the instruction that the given
* opcode maps to.
*/
void
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mos6502_dis_instruction(FILE *stream, int inst_code)
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{
// Arguably this could or should be done as fputs(), which is
// presumably a simpler output method. But, since we use fprintf()
// in other places, I think we should continue to do so. Further, we
// use a simple format string (%s) to avoid the linter's complaints
// about potential security issues.
fprintf(stream, "%s", instruction_strings[inst_code]);
}
/*
* This function returns the number of bytes that the given opcode is
* expecting to work with. For instance, if the opcode is in absolute
* address mode, then we will need to read the next two bytes in the
* stream to compose a full 16-bit address to work with. If our opcode
* is in immediate mode, then we only need to read one byte. Many
* opcodes will read no bytes at all from the stream (in which we return
* zero).
*/
int
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mos6502_dis_expected_bytes(int addr_mode)
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{
switch (addr_mode) {
// These are 16-bit operands, because they work with absolute
// addresses in memory.
case ABS:
case ABY:
case ABX:
case IND:
return 2;
// These are the 8-bit operand address modes.
case IMM:
case IDX:
case IDY:
case REL:
case ZPG:
case ZPX:
case ZPY:
return 1;
// These two address modes have implied arguments; ACC is
// the accumulator, and IMP basically means it operates on
// some specific (presumably obvious) thing and no operand
// is necessary.
case ACC:
case IMP:
return 0;
}
// I don't know how we got here, outside of foul magicks and cruel
// trickery. Let's fearfully return zero!
return 0;
}
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/*
* Scan the segment (with a given address) and write the opcode at that
* point to the given file stream. This function will also write an
* operand to the file stream if one is warranted. We return the number
* of bytes consumed by scanning past the opcode and/or operand.
*/
int
mos6502_dis_opcode(FILE *stream, vm_segment *segment, int address)
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{
vm_8bit opcode;
vm_16bit operand;
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int addr_mode;
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int inst_code;
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int expected;
// The next byte is assumed to be the opcode we work with.
opcode = vm_segment_get(segment, address);
// And given that opcode, we need to see how many bytes large our
// operand will be.
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addr_mode = mos6502_addr_mode(opcode);
expected = mos6502_dis_expected_bytes(addr_mode);
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// The specific instruction we mean to execute
inst_code = mos6502_instruction(opcode);
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// The operand itself defaults to zero... in cases where this
// doesn't change, the instruction related to the opcode will
// probably not even use it.
operand = 0;
// And we need to skip ahead of the opcode.
address++;
switch (expected) {
case 2:
// If we have a two-byte operand, then the first byte is the
// MSB and our operand will need to shift it 8 positions to
// the left before it can be OR'd.
operand |= vm_segment_get(segment, address) << 8;
address++;
// Note we fall through here to the next case...
case 1:
// If it's a one-byte operand, then this byte should occupy
// the LSB space which simply requires we OR the byte
// directly in. If this is part of a two-byte operand, then
// the same logic still applies.
operand |= vm_segment_get(segment, address);
address++;
// And, in any other case (e.g. 0), we are done; we don't
// read anything, and we leave the operand as it is.
default:
break;
}
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// If the stream is NULL, we're doing some kind of lookahead.
// Furthermore, if this is an instruction that would switch control
// to a different spot in the program, then let's label this in the
// jump table.
if (stream == NULL && mos6502_would_jump(inst_code)) {
mos6502_dis_jump_label(operand, address, addr_mode);
}
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// It's totally possible that we are not expected to print out the
// contents of our inspection of the opcode. (For example, we may
// just want to set the jump table in a lookahead operation.)
if (stream) {
// Hey! We might have a label at this position in the code. If
// so, let's print out the label.
if (jump_table[address]) {
// This will print out just the label itself.
mos6502_dis_label(stream, address);
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// But to actually define the label, we need a colon to
// complete the notation. (We don't _need_ a newline, but it
// looks nicer to my arbitrary sensibilities. Don't @ me!)
fprintf(stream, ":\n");
}
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// Let's print out to the stream what we have so far. First, we
// indent by four spaces.
fprintf(stream, " ");
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// Print out the instruction code that our opcode represents.
mos6502_dis_instruction(stream, inst_code);
if (expected) {
// Let's "tab" over; each instruction code is 3 characters, so let's
// move over 5 spaces (4 spaces indent + 1, just to keep everything
// aligned by 4-character boundaries).
fprintf(stream, " ");
// Print out the operand given the proper address mode.
mos6502_dis_operand(stream, address, addr_mode, operand);
}
// And let's terminate the line.
fprintf(stream, "\n");
}
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// The expected number of bytes here is for the operand, but we need
// to add one for the opcode to return the true number that this
// opcode sequence would consume.
return expected + 1;
}
void
mos6502_dis_scan(FILE *stream, vm_segment *segment, int pos, int end)
{
while (pos < end) {
pos += mos6502_dis_opcode(stream, segment, pos);
}
}
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void
mos6502_dis_jump_label(vm_16bit operand, int address, int addr_mode)
{
int jump_loc = operand;
if (addr_mode == REL) {
jump_loc = address + operand;
if (operand > 127) {
jump_loc -= 256;
}
}
jump_table[jump_loc] = 1;
}
inline void
mos6502_dis_label(FILE *stream, int address)
{
fprintf(stream, "ADDR_%d", address);
}
inline void
mos6502_dis_jump_unlabel(int address)
{
jump_table[address] = 0;
}
inline bool
mos6502_dis_is_jump_label(int address)
{
return jump_table[address] == 1;
}