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MemCpyOptimizer: Use max legal int size instead of pointer size
If there are no legal integers, assume 1 byte. This makes more sense than using the pointer size as a guess for the maximum GPR width. It is conceivable to want to use some 64-bit pointers on a target where 64-bit integers aren't legal. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@190817 91177308-0d34-0410-b5e6-96231b3b80d8
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@@ -170,14 +170,17 @@ bool MemsetRange::isProfitableToUseMemset(const DataLayout &TD) const {
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// pessimize the llvm optimizer.
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//
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// Since we don't have perfect knowledge here, make some assumptions: assume
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// the maximum GPR width is the same size as the pointer size and assume that
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// this width can be stored. If so, check to see whether we will end up
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// actually reducing the number of stores used.
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// the maximum GPR width is the same size as the largest legal integer
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// size. If so, check to see whether we will end up actually reducing the
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// number of stores used.
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unsigned Bytes = unsigned(End-Start);
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unsigned NumPointerStores = Bytes/TD.getPointerSize();
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unsigned MaxIntSize = TD.getLargestLegalIntTypeSize();
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if (MaxIntSize == 0)
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MaxIntSize = 1;
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unsigned NumPointerStores = Bytes / MaxIntSize;
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// Assume the remaining bytes if any are done a byte at a time.
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unsigned NumByteStores = Bytes - NumPointerStores*TD.getPointerSize();
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unsigned NumByteStores = Bytes - NumPointerStores * MaxIntSize;
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// If we will reduce the # stores (according to this heuristic), do the
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// transformation. This encourages merging 4 x i8 -> i32 and 2 x i16 -> i32
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