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Fix a XOR reassociation bug.
When Reassociator optimize "(x | C1)" ^ "(X & C2)", it may swap the two subexpressions, however, it forgot to swap cached constants (of C1 and C2) accordingly. rdar://13739160 git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@180676 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -1195,9 +1195,6 @@ bool Reassociate::CombineXorOpnd(Instruction *I, XorOpnd *Opnd1, XorOpnd *Opnd2,
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if (X != Opnd2->getSymbolicPart())
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return false;
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const APInt &C1 = Opnd1->getConstPart();
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const APInt &C2 = Opnd2->getConstPart();
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// This many instruction become dead.(At least "Opnd1 ^ Opnd2" will die.)
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int DeadInstNum = 1;
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if (Opnd1->getValue()->hasOneUse())
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@ -1215,6 +1212,8 @@ bool Reassociate::CombineXorOpnd(Instruction *I, XorOpnd *Opnd1, XorOpnd *Opnd2,
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if (Opnd2->isOrExpr())
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std::swap(Opnd1, Opnd2);
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const APInt &C1 = Opnd1->getConstPart();
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const APInt &C2 = Opnd2->getConstPart();
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APInt C3((~C1) ^ C2);
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// Do not increase code size!
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@ -1230,6 +1229,8 @@ bool Reassociate::CombineXorOpnd(Instruction *I, XorOpnd *Opnd1, XorOpnd *Opnd2,
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} else if (Opnd1->isOrExpr()) {
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// Xor-Rule 3: (x | c1) ^ (x | c2) = (x & c3) ^ c3 where c3 = c1 ^ c2
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//
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const APInt &C1 = Opnd1->getConstPart();
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const APInt &C2 = Opnd2->getConstPart();
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APInt C3 = C1 ^ C2;
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// Do not increase code size
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@ -1244,6 +1245,8 @@ bool Reassociate::CombineXorOpnd(Instruction *I, XorOpnd *Opnd1, XorOpnd *Opnd2,
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} else {
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// Xor-Rule 4: (x & c1) ^ (x & c2) = (x & (c1^c2))
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//
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const APInt &C1 = Opnd1->getConstPart();
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const APInt &C2 = Opnd2->getConstPart();
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APInt C3 = C1 ^ C2;
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Res = createAndInstr(I, X, C3);
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}
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@ -164,3 +164,30 @@ define void @xor_bug1() {
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%3 = and i64 undef, %2
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ret void
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}
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; The bug was that when the compiler optimize "(x | c1)" ^ "(x & c2)", it may
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; swap the two xor-subexpressions if they are not in canoninical order; however,
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; when optimizer swaps two sub-expressions, if forgot to swap the cached value
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; of c1 and c2 accordingly, hence cause the problem.
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;
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define i32 @xor_bug2(i32, i32, i32, i32) {
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%5 = mul i32 %0, 123
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%6 = add i32 %2, 24
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%7 = add i32 %1, 8
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%8 = and i32 %1, 3456789
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%9 = or i32 %8, 4567890
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%10 = and i32 %1, 543210987
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%11 = or i32 %1, 891034567
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%12 = and i32 %2, 255
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%13 = xor i32 %9, %10
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%14 = xor i32 %11, %13
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%15 = xor i32 %5, %14
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%16 = and i32 %3, 255
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%17 = xor i32 %16, 42
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%18 = add i32 %6, %7
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%19 = add i32 %18, %12
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%20 = add i32 %19, %15
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ret i32 %20
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;CHECK: @xor_bug2
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;CHECK: xor i32 %5, 891034567
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}
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