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Tighten up assertion checking for binary operators, not allowing invalid
instructions to _even be created_. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@3661 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -17,11 +17,36 @@ BinaryOperator::BinaryOperator(BinaryOps iType, Value *S1, Value *S2,
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const Type *Ty, const std::string &Name,
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Instruction *InsertBefore)
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: Instruction(Ty, iType, Name, InsertBefore) {
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Operands.reserve(2);
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Operands.push_back(Use(S1, this));
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Operands.push_back(Use(S2, this));
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assert(Operands[0] && Operands[1] &&
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Operands[0]->getType() == Operands[1]->getType());
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assert(S1 && S2 && S1->getType() == S2->getType());
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#ifndef NDEBUG
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switch (iType) {
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case Add: case Sub:
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case Mul: case Div:
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case Rem:
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assert(Ty == S1->getType() &&
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"Arithmetic operation should return same type as operands!");
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assert((Ty->isInteger() || Ty->isFloatingPoint()) &&
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"Tried to create an arithmetic operation on a non-arithmetic type!");
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break;
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case And: case Or:
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case Xor:
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assert(Ty == S1->getType() &&
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"Logical operation should return same type as operands!");
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assert(Ty->isIntegral() &&
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"Tried to create an logical operation on a non-integral type!");
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break;
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case SetLT: case SetGT: case SetLE:
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case SetGE: case SetEQ: case SetNE:
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assert(Ty == Type::BoolTy && "Setcc must return bool!");
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default:
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break;
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}
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#endif
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}
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