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Remove an assertion that uses Type::TypeTy that is never hit and will

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break when Type::TypeTy goes away. Also remove a dead block of code and
dead comments.


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@13861 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Reid Spencer 2004-05-27 22:05:50 +00:00
parent 73b7495a96
commit 9ed0f17a62
1 changed files with 1 additions and 12 deletions
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13
lib/AsmParser/llvmAsmParser.y
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@ -377,7 +377,6 @@ static Value *getValNonImprovising(const Type *Ty, const ValID &D) {
// real thing.
//
static Value *getVal(const Type *Ty, const ValID &D) {
assert(Ty != Type::TypeTy && "Should use getTypeVal for types!");
// See if the value has already been defined...
Value *V = getValNonImprovising(Ty, D);
@ -519,17 +518,7 @@ static bool setValueName(Value *V, char *NameStr) {
Value *Existing = ST.lookup(V->getType(), Name);
if (Existing) { // Inserting a name that is already defined???
// There is only one case where this is allowed: when we are refining an
// opaque type. In this case, Existing will be an opaque type.
if (const Type *Ty = dyn_cast<Type>(Existing)) {
if (const OpaqueType *OpTy = dyn_cast<OpaqueType>(Ty)) {
// We ARE replacing an opaque type!
((OpaqueType*)OpTy)->refineAbstractTypeTo(cast<Type>(V));
return true;
}
}
// Otherwise, we are a simple redefinition of a value, check to see if it
// We are a simple redefinition of a value, check to see if it
// is defined the same as the old one...
if (const Type *Ty = dyn_cast<Type>(Existing)) {
if (Ty == cast<Type>(V)) return true; // Yes, it's equal.