Fixed instruction information for RDCCR and WRCCR.

Fixed selection to create a TmpInstruction for each integer CC register
(since it is an implicit side-effect, unlike FP CC registers which are
explicit operands).


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@1120 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Vikram S. Adve 2001-11-04 19:34:49 +00:00
parent 8e7f409169
commit b7f06f46a1
3 changed files with 128 additions and 59 deletions

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@ -426,15 +426,14 @@ I(CALL , "call", 1, -1, B29, true , 1, 2, SPARC_CTI, M_BRANCH_FLAG | M_CALL_F
I(JMPLCALL, "jmpl", 3, -1, B12, true , 1, 2, SPARC_CTI, M_BRANCH_FLAG | M_CALL_FLAG )
I(JMPLRET, "jmpl", 3, -1, B12, true , 1, 2, SPARC_CTI, M_BRANCH_FLAG | M_RET_FLAG)
I(RETURN, "return", 2, -1, 0, false, 1, 2, SPARC_CTI, M_BRANCH_FLAG | M_RET_FLAG)
// SAVE and restore instructions
I(SAVE , "save", 3, 2, B12, true , 0, 1, SPARC_SINGLE, M_INT_FLAG | M_ARITH_FLAG)
I(RESTORE, "restore", 3, 2, B12, true , 0, 1, SPARC_SINGLE, M_INT_FLAG | M_ARITH_FLAG)
// Read and Write CCR register from/to an int reg
I(RDCCR, "rd", 2, 1, 0, false, 0, 1, SPARC_IEUN, M_INT_FLAG)
I(WRCCR, "wr", 3, 2, 0, false, 0, 1, SPARC_IEUN, M_INT_FLAG)
I(RDCCR, "rd", 2, 1, 0, false, 0, 1, SPARC_SINGLE, M_INT_FLAG | M_CC_FLAG)
I(WRCCR, "wr", 3, 2, 0, false, 0, 1, SPARC_SINGLE, M_INT_FLAG | M_CC_FLAG)
// Synthetic phi operation for near-SSA form of machine code
// Number of operands is variable, indicated by -1. Result is the first op.

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@ -134,6 +134,39 @@ ChooseBFpccInstruction(const InstructionNode* instrNode,
}
// Create a unique TmpInstruction for a boolean value,
// representing the CC register used by a branch on that value.
// For now, hack this using a little static cache of TmpInstructions.
// Eventually the entire BURG instruction selection should be put
// into a separate class that can hold such information.
// The static cache is not too bad because that memory for these
// TmpInstructions will be freed elsewhere in any case.
//
static TmpInstruction*
GetTmpForCC(Value* boolVal, const Method* method)
{
typedef hash_map<const Value*, TmpInstruction*> BoolTmpCache;
static BoolTmpCache boolToTmpCache; // Map boolVal -> TmpInstruction*
static const Method* lastMethod = NULL; // Use to flush cache between methods
assert(boolVal->getType() == Type::BoolTy && "Weird but ok! Delete assert");
if (lastMethod != method)
{
lastMethod = method;
boolToTmpCache.clear();
}
// Look for tmpI and create a new one otherswise.
// new value is directly written to map using
TmpInstruction*& tmpI = boolToTmpCache[boolVal];
if (tmpI == NULL)
tmpI = new TmpInstruction(TMP_INSTRUCTION_OPCODE, boolVal, NULL);
return tmpI;
}
static inline MachineOpCode
ChooseBccInstruction(const InstructionNode* instrNode,
bool& isFPBranch)
@ -1123,12 +1156,12 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
switch(ruleForNode) {
case 1: // stmt: Ret
case 2: // stmt: RetValue(reg)
// NOTE: Prepass of register allocation is responsible
{ // NOTE: Prepass of register allocation is responsible
// for moving return value to appropriate register.
// Mark the return-address register as a hidden virtual reg.
// Mark the return value register as an implicit ref of
// the machine instruction.
{ // Finally put a NOP in the delay slot.
// Finally put a NOP in the delay slot.
ReturnInst* returnInstr = (ReturnInst*) subtreeRoot->getInstruction();
assert(returnInstr->getOpcode() == Instruction::Ret);
Method* method = returnInstr->getParent()->getParent();
@ -1150,7 +1183,7 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
mvec[n] = new MachineInstr(NOP);
break;
}
}
case 3: // stmt: Store(reg,reg)
case 4: // stmt: Store(reg,ptrreg)
@ -1172,11 +1205,11 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
break;
case 206: // stmt: BrCond(setCCconst)
// setCCconst => boolean was computed with `%b = setCC type reg1 const'
{ // setCCconst => boolean was computed with `%b = setCC type reg1 const'
// If the constant is ZERO, we can use the branch-on-integer-register
// instructions and avoid the SUBcc instruction entirely.
// Otherwise this is just the same as case 5, so just fall through.
{
//
InstrTreeNode* constNode = subtreeRoot->leftChild()->rightChild();
assert(constNode &&
constNode->getNodeType() ==InstrTreeNode::NTConstNode);
@ -1188,13 +1221,15 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
&& GetConstantValueAsSignedInt(constVal, isValidConst) == 0
&& isValidConst)
{
BranchInst* brInst=cast<BranchInst>(subtreeRoot->getInstruction());
// That constant is a zero after all...
// Use the left child of setCC as the first argument!
mvec[0] = new MachineInstr(ChooseBprInstruction(subtreeRoot));
mvec[0]->SetMachineOperand(0, MachineOperand::MO_VirtualRegister,
subtreeRoot->leftChild()->leftChild()->getValue());
mvec[0]->SetMachineOperand(1, MachineOperand::MO_PCRelativeDisp,
((BranchInst*) subtreeRoot->getInstruction())->getSuccessor(0));
brInst->getSuccessor(0));
// delay slot
mvec[numInstr++] = new MachineInstr(NOP);
@ -1205,7 +1240,7 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
mvec[n]->SetMachineOperand(0, MachineOperand::MO_CCRegister,
(Value*) NULL);
mvec[n]->SetMachineOperand(1, MachineOperand::MO_PCRelativeDisp,
((BranchInst*) subtreeRoot->getInstruction())->getSuccessor(1));
brInst->getSuccessor(1));
// delay slot
mvec[numInstr++] = new MachineInstr(NOP);
@ -1213,41 +1248,47 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
break;
}
// ELSE FALL THROUGH
}
}
case 6: // stmt: BrCond(bool)
// bool => boolean was computed with some boolean operator
{ // bool => boolean was computed with some boolean operator
// (SetCC, Not, ...). We need to check whether the type was a FP,
// signed int or unsigned int, and check the branching condition in
// order to choose the branch to use.
// If it is an integer CC, we also need to find the unique
// TmpInstruction representing that CC.
//
{
BranchInst* brInst = cast<BranchInst>(subtreeRoot->getInstruction());
bool isFPBranch;
mvec[0] = new MachineInstr(ChooseBccInstruction(subtreeRoot,
isFPBranch));
mvec[0]->SetMachineOperand(0, MachineOperand::MO_CCRegister,
subtreeRoot->leftChild()->getValue());
Value* ccValue = isFPBranch? subtreeRoot->leftChild()->getValue()
: GetTmpForCC(subtreeRoot->leftChild()->getValue(),
brInst->getParent()->getParent());
mvec[0]->SetMachineOperand(0, MachineOperand::MO_CCRegister, ccValue);
mvec[0]->SetMachineOperand(1, MachineOperand::MO_PCRelativeDisp,
((BranchInst*) subtreeRoot->getInstruction())->getSuccessor(0));
brInst->getSuccessor(0));
// delay slot
mvec[numInstr++] = new MachineInstr(NOP);
// false branch
int n = numInstr++;
mvec[n] = new MachineInstr(BA);
mvec[n]->SetMachineOperand(0, MachineOperand::MO_CCRegister,
(Value*) NULL);
mvec[n]->SetMachineOperand(1, MachineOperand::MO_PCRelativeDisp,
((BranchInst*) subtreeRoot->getInstruction())->getSuccessor(1));
brInst->getSuccessor(1));
// delay slot
mvec[numInstr++] = new MachineInstr(NOP);
break;
}
}
case 208: // stmt: BrCond(boolconst)
{
{
// boolconst => boolean is a constant; use BA to first or second label
ConstPoolVal* constVal =
cast<ConstPoolVal>(subtreeRoot->leftChild()->getValue());
@ -1262,13 +1303,12 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
// delay slot
mvec[numInstr++] = new MachineInstr(NOP);
break;
}
}
case 8: // stmt: BrCond(boolreg)
// boolreg => boolean is stored in an existing register.
{ // boolreg => boolean is stored in an existing register.
// Just use the branch-on-integer-register instruction!
//
{
mvec[0] = new MachineInstr(BRNZ);
mvec[0]->SetMachineOperand(0, MachineOperand::MO_VirtualRegister,
subtreeRoot->leftChild()->getValue());
@ -1289,7 +1329,7 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
// delay slot
mvec[numInstr++] = new MachineInstr(NOP);
break;
}
}
case 9: // stmt: Switch(reg)
assert(0 && "*** SWITCH instruction is not implemented yet.");
@ -1518,24 +1558,32 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
case 42: // bool: SetCC(reg, reg):
{
// If result of the SetCC is only used for a single branch, we can
// discard the boolean result and keep only the condition code.
// Otherwise, the boolean value must go into an integer register.
// To put the boolean result in a register we use a conditional move,
// unless the result of the SUBCC instruction can be used as the bool!
// This assumes that zero is FALSE and any non-zero integer is TRUE.
// This generates a SUBCC instruction, putting the difference in
// a result register, and setting a condition code.
//
bool keepBoolVal = (subtreeRoot->parent() == NULL ||
((InstructionNode*) subtreeRoot->parent())
->getInstruction()->getOpcode() !=Instruction::Br);
bool subValIsBoolVal =
subtreeRoot->getInstruction()->getOpcode() == Instruction::SetNE;
// If the boolean result of the SetCC is used by anything other
// than a single branch instruction, the boolean must be
// computed and stored in the result register. Otherwise, discard
// the difference (by using %g0) and keep only the condition code.
//
// To compute the boolean result in a register we use a conditional
// move, unless the result of the SUBCC instruction can be used as
// the bool! This assumes that zero is FALSE and any non-zero
// integer is TRUE.
//
InstructionNode* parentNode = (InstructionNode*) subtreeRoot->parent();
Instruction* setCCInstr = subtreeRoot->getInstruction();
bool keepBoolVal = (parentNode == NULL ||
parentNode->getInstruction()->getOpcode()
!= Instruction::Br);
bool subValIsBoolVal = setCCInstr->getOpcode() == Instruction::SetNE;
bool keepSubVal = keepBoolVal && subValIsBoolVal;
bool computeBoolVal = keepBoolVal && ! subValIsBoolVal;
bool mustClearReg;
int valueToMove;
MachineOpCode movOpCode;
Value* ccValue = NULL;
if (subtreeRoot->leftChild()->getValue()->getType()->isIntegral() ||
subtreeRoot->leftChild()->getValue()->getType()->isPointerType())
@ -1548,22 +1596,32 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
mvec[0] = new MachineInstr(SUBcc);
Set3OperandsFromInstr(mvec[0], subtreeRoot, target, ! keepSubVal);
// mark the 4th operand as being a CC register, and a "result"
// Mark the 4th operand as being a CC register, and as a def
// A TmpInstruction is created to represent the int CC "result".
// Unlike other instances of TmpInstruction, this one is used by
// used by machine code of multiple LLVM instructions, viz.,
// the SetCC and the branch. Make sure to get the same one!
//
TmpInstruction* tmpForCC = GetTmpForCC(setCCInstr,
setCCInstr->getParent()->getParent());
setCCInstr->getMachineInstrVec().addTempValue(tmpForCC);
mvec[0]->SetMachineOperand(3, MachineOperand::MO_CCRegister,
subtreeRoot->getValue(),/*def*/true);
tmpForCC, /*def*/true);
if (computeBoolVal)
{ // recompute bool using the integer condition codes
movOpCode =
ChooseMovpccAfterSub(subtreeRoot,mustClearReg,valueToMove);
ccValue = tmpForCC;
}
}
else
{
// FP condition: dest of FCMP should be some FCCn register
mvec[0] = new MachineInstr(ChooseFcmpInstruction(subtreeRoot));
mvec[0]->SetMachineOperand(0,MachineOperand::MO_CCRegister,
subtreeRoot->getValue());
mvec[0]->SetMachineOperand(0, MachineOperand::MO_CCRegister,
setCCInstr);
mvec[0]->SetMachineOperand(1,MachineOperand::MO_VirtualRegister,
subtreeRoot->leftChild()->getValue());
mvec[0]->SetMachineOperand(2,MachineOperand::MO_VirtualRegister,
@ -1574,11 +1632,14 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
mustClearReg = true;
valueToMove = 1;
movOpCode = ChooseMovFpccInstruction(subtreeRoot);
ccValue = setCCInstr;
}
}
if (computeBoolVal)
{
assert(ccValue && "Inconsistent logic above and here");
if (mustClearReg)
{// Unconditionally set register to 0
int n = numInstr++;
@ -1586,18 +1647,18 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
mvec[n]->SetMachineOperand(0,MachineOperand::MO_UnextendedImmed,
s0);
mvec[n]->SetMachineOperand(1,MachineOperand::MO_VirtualRegister,
subtreeRoot->getValue());
setCCInstr);
}
// Now conditionally move `valueToMove' (0 or 1) into the register
int n = numInstr++;
mvec[n] = new MachineInstr(movOpCode);
mvec[n]->SetMachineOperand(0, MachineOperand::MO_CCRegister,
subtreeRoot->getValue());
ccValue);
mvec[n]->SetMachineOperand(1, MachineOperand::MO_UnextendedImmed,
valueToMove);
mvec[n]->SetMachineOperand(2, MachineOperand::MO_VirtualRegister,
subtreeRoot->getValue());
setCCInstr);
}
break;
}
@ -1637,8 +1698,8 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
SetOperandsForMemInstr(mvec[0], subtreeRoot, target);
break;
case 57: // reg: Alloca: Implement as 1 instruction:
{ // add %fp, offsetFromFP -> result
case 57: // reg: Alloca: Implement as 1 instruction:
{ // add %fp, offsetFromFP -> result
Instruction* instr = subtreeRoot->getInstruction();
const PointerType* instrType = (const PointerType*) instr->getType();
assert(instrType->isPointerType());
@ -1666,12 +1727,12 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
mvec[0]->SetMachineOperand(2, MachineOperand::MO_VirtualRegister,
instr);
break;
}
}
case 58: // reg: Alloca(reg): Implement as 3 instructions:
// mul num, typeSz -> tmp
// sub %sp, tmp -> %sp
{ // add %sp, frameSizeBelowDynamicArea -> result
{ // add %sp, frameSizeBelowDynamicArea -> result
Instruction* instr = subtreeRoot->getInstruction();
const PointerType* instrType = (const PointerType*) instr->getType();
assert(instrType->isPointerType() &&
@ -1730,17 +1791,17 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
lowerAreaSizeVal);
mvec[2]->SetMachineOperand(2,MachineOperand::MO_VirtualRegister,instr);
break;
}
}
case 61: // reg: Call
// Generate a call-indirect (i.e., jmpl) for now to expose
{ // Generate a call-indirect (i.e., jmpl) for now to expose
// the potential need for registers. If an absolute address
// is available, replace this with a CALL instruction.
// Mark both the indirection register and the return-address
// register as hidden virtual registers.
// Also, mark the operands of the Call and return value (if
// any) as implicit operands of the CALL machine instruction.
{
//
CallInst *callInstr = cast<CallInst>(subtreeRoot->getInstruction());
Value *callee = callInstr->getCalledValue();
@ -1792,7 +1853,7 @@ GetInstructionsByRule(InstructionNode* subtreeRoot,
mvec[numInstr++] = new MachineInstr(NOP); // delay slot
break;
}
}
case 62: // reg: Shl(reg, reg)
opType = subtreeRoot->leftChild()->getValue()->getType();

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@ -871,10 +871,6 @@ const InstrIssueDelta SparcInstrIssueDeltas[] = {
{ RETURN, true, true, 0 },
//{ DONE, true, true, 0 },
//{ RETRY, true, true, 0 },
//{ WR, true, true, 0 },
//{ WRPR, true, true, 4 },
//{ RD, true, true, 0 },
//{ RDPR, true, true, 0 },
//{ TCC, true, true, 0 },
//{ SHUTDOWN, true, true, 0 },
@ -902,8 +898,10 @@ const InstrIssueDelta SparcInstrIssueDeltas[] = {
{ UDIVX, true, true, 68 },
//{ SDIVcc, true, true, 36 },
//{ UDIVcc, true, true, 37 },
//{ WR, false, false, 4 },
//{ WRPR, false, false, 4 },
{ WRCCR, true, true, 4 },
//{ WRPR, true, true, 4 },
//{ RDCCR, true, true, 0 }, // no bubbles after, but see below
//{ RDPR, true, true, 0 },
};
@ -950,7 +948,7 @@ const InstrRUsageDelta SparcInstrUsageDeltas[] = {
//
// Some instructions are stalled in the GROUP stage if a CTI is in
// the E or C stage
// the E or C stage. We model that with a fake resource CTIDelayCycle.
//
{ LDD, CTIDelayCycle.rid, 1, 1 },
//{ LDDA, CTIDelayCycle.rid, 1, 1 },
@ -976,6 +974,17 @@ const InstrRUsageDelta SparcInstrUsageDeltas[] = {
{ LDSW, LdReturn.rid, 2, -1 },
{ LDSW, LdReturn.rid, 3, 1 },
//
// RDPR from certain registers and RD from any register are not dispatchable
// until four clocks after they reach the head of the instr. buffer.
// Together with their single-issue requirement, this means all four issue
// slots are effectively blocked for those cycles, plus the issue cycle.
// This does not increase the latency of the instruction itself.
//
{ RDCCR, AllIssueSlots.rid, 0, 5 },
{ RDCCR, AllIssueSlots.rid, 0, 5 },
{ RDCCR, AllIssueSlots.rid, 0, 5 },
{ RDCCR, AllIssueSlots.rid, 0, 5 },
#undef EXPLICIT_BUBBLES_NEEDED
#ifdef EXPLICIT_BUBBLES_NEEDED