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[x86] Fix disassembly of callw instruction

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Not quite sure why this was marked isAsmParserOnly, but it means that the
disassembler can't see it either.

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@199651 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
David Woodhouse 2014-01-20 12:02:40 +00:00
parent 7360e8caa3
commit d1c3f6664e
2 changed files with 6 additions and 8 deletions
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10
lib/Target/X86/X86InstrControl.td
View File

@ -186,6 +186,10 @@ let isCall = 1 in
(outs), (ins i32imm_pcrel:$dst),
"call{l}\t$dst", [], IIC_CALL_RI>, OpSize16,
Requires<[Not64BitMode]>, Sched<[WriteJump]>;
def CALLpcrel16 : Ii16PCRel<0xE8, RawFrm,
(outs), (ins i16imm_pcrel:$dst),
"call{w}\t$dst", [], IIC_CALL_RI>, OpSize,
Sched<[WriteJump]>;
def CALL16r : I<0xFF, MRM2r, (outs), (ins GR16:$dst),
"call{w}\t{*}$dst", [(X86call GR16:$dst)], IIC_CALL_RI>,
OpSize, Requires<[Not64BitMode]>, Sched<[WriteJump]>;
@ -218,12 +222,6 @@ let isCall = 1 in
def FARCALL32m : I<0xFF, MRM3m, (outs), (ins opaque48mem:$dst),
"lcall{l}\t{*}$dst", [], IIC_CALL_FAR_MEM>, OpSize16,
Sched<[WriteJumpLd]>;
// callw for 16 bit code for the assembler.
let isAsmParserOnly = 1 in
def CALLpcrel16 : Ii16PCRel<0xE8, RawFrm,
(outs), (ins i16imm_pcrel:$dst),
"callw\t$dst", []>, OpSize;
}

4
test/MC/Disassembler/X86/x86-16.txt
View File

@ -492,8 +492,8 @@
# CHECK: calll
0x66 0xe8 0x00 0x00 0x00 0x00
# CHECKX: callw
#0xe8 0x00 0x00
# CHECK: callw
0xe8 0x00 0x00
# CHECK: incb %al
0xfe 0xc0