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Get rid of leading zeros in the output of toString.

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git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@37175 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Reid Spencer 2007-05-17 19:23:02 +00:00
parent fd30eee2f0
commit fb0709a180
1 changed files with 27 additions and 8 deletions
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35
lib/Support/APInt.cpp
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@ -1938,14 +1938,33 @@ std::string APInt::toString(uint8_t radix, bool wantSigned) const {
}
if (radix != 10) {
uint64_t mask = radix - 1;
uint32_t shift = (radix == 16 ? 4 : radix == 8 ? 3 : 1);
uint32_t nibbles = APINT_BITS_PER_WORD / shift;
for (uint32_t i = 0; i < getNumWords(); ++i) {
uint64_t value = pVal[i];
for (uint32_t j = 0; j < nibbles; ++j) {
result.insert(0, digits[ value & mask ]);
value >>= shift;
// For the 2, 8 and 16 bit cases, we can just shift instead of divide
// because the number of bits per digit (1,3 and 4 respectively) divides
// equaly. We just shift until there value is zero.
// First, check for a zero value and just short circuit the logic below.
if (*this == 0)
result = "0";
else {
APInt tmp(*this);
size_t insert_at = 0;
if (wantSigned && this->isNegative()) {
// They want to print the signed version and it is a negative value
// Flip the bits and add one to turn it into the equivalent positive
// value and put a '-' in the result.
tmp.flip();
tmp++;
result = "-";
insert_at = 1;
}
// Just shift tmp right for each digit width until it becomes zero
uint32_t shift = (radix == 16 ? 4 : (radix == 8 ? 3 : 1));
uint64_t mask = radix - 1;
APInt zero(tmp.getBitWidth(), 0);
while (tmp.ne(zero)) {
unsigned digit = tmp.getZExtValue() & mask;
tmp = tmp.lshr(shift);
result.insert(insert_at, digits[digit]);
}
}
return result;