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od: fix printing of high-bit chars 

Example: echo £ | od -c

Signed-off-by: Ron Yorston <rmy@tigress.co.uk>
Signed-off-by: Denys Vlasenko <vda.linux@googlemail.com>
This commit is contained in:
Ron Yorston 2015-03-12 20:10:40 +01:00 committed by Denys Vlasenko
parent 8dff01d06a
commit 53e9c51ade
1 changed files with 6 additions and 8 deletions
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14
coreutils/od_bloaty.c
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@ -387,11 +387,11 @@ print_named_ascii(size_t n_bytes, const char *block,
" sp"
};
// buf[N] pos: 01234 56789
char buf[12] = " x\0 0xx\0";
// actually " x\0 xxx\0", but want to share string with print_ascii.
char buf[12] = " x\0 xxx\0";
// [12] because we take three 32bit stack slots anyway, and
// gcc is too dumb to initialize with constant stores,
// it copies initializer from rodata. Oh well.
// https://gcc.gnu.org/bugzilla/show_bug.cgi?id=65410
while (n_bytes--) {
unsigned masked_c = *(unsigned char *) block++;
@ -419,7 +419,7 @@ print_ascii(size_t n_bytes, const char *block,
const char *unused_fmt_string UNUSED_PARAM)
{
// buf[N] pos: 01234 56789
char buf[12] = " x\0 0xx\0";
char buf[12] = " x\0 xxx\0";
while (n_bytes--) {
const char *s;
@ -455,11 +455,9 @@ print_ascii(size_t n_bytes, const char *block,
case '\v':
s = " \\v";
break;
case '\x7f':
s = " 177";
break;
default: /* c is never larger than 040 */
buf[7] = (c >> 3) + '0';
default:
buf[6] = (c >> 6 & 3) + '0';
buf[7] = (c >> 3 & 7) + '0';
buf[8] = (c & 7) + '0';
s = buf + 5;
}