dingusppc/zdocs/machines/pdmram.md

4.7 KiB

RAM Expansion in Power Macintosh 6100

Power Macintosh 6100 comes with two RAM slots accepting 72-pin SIMMs.

Because a 72-pin SIMM only has 32 data lines but the PowerPC CPU bus is 64-bit wide two SIMMs with the same capacity installed in both slots are required.

Moreover, each 72-pin SIMM can have one or two banks of memory. RAM banks are not to be confused with memory slots on the motherboard! A single bank SIMM will have only one side populated with RAM chips while a two banks SIMM will contain chips on both sides.

A 72-pin SIMM has 12 address lines so the maximum amount of RAM one bank can hold is calculated as follows:

2^row_bits * 2^column_bits * (bus_width/8) = 2^12 * 2^12 * 8 = 128 MB

Considering two banks of memory the maximum amount of RAM one can plug into a Power Macintosh 6100 is 256 MB.

Both parity (36bit) and non-parity (32bit) SIMMs should work fine in this machine.

Always use two SIMMs with the same configuration and capacity to extend the RAM in your Power Macintosh 6100!

Supported SIMM sizes

Power Macintosh 6100 supports the following SIMM sizes and configurations:

Bank size Number of rows Number of columns Total RAM
1 MB 9 9 2 MB
2 MB 10 9 4 MB
4 MB 10 10 8 MB
8 MB 11 10 16 MB
16 MB 11 11 32 MB
16 MB 12 10 32 MB
32 MB 12 11 64 MB
64 MB 12 12 128 MB

RAM sizing

Although the 72-pin SIMM provides four identification aka presence detection pins the Power Macintosh 6100 motherboard actually leaves them unconnected.

To determine the size of installed RAM the low-level software in the computer's ROM runs a specialized procedure called RAM sizing.

Its algorithm proceeds as follows:

  1. set physical bank size to 128 MB so the memory controller will drive all row and column bits
  2. write a 64-bit test pattern to the last QWORD of each physical bank
  3. if the test pattern can be read back assume some memory is present; proceed with step 5
  4. decrement memory address and return to step 2 or exit if no memory was found
  5. search upwards for the first occurence of the test pattern written in step 2 starting with the first address of the particular bank; the first location the test pattern can be found at indicates the size of the installed memory.

To fully understand the above algorithm let's work through the following example:

Step 2 writes a QWORD at offset 0x07FFFFF8 that corresponds to 128 MB - 8. The Highspeed Memory Controller (HMC) decodes that offset as follows:

aaaaa | rrrrrrrrrrrr | cccccccccccc | lll
------------------------------------------
00000 | 111111111111 | 111111111111 | 000

where a indicates the bank starting address, r corresponds to the row bits, c - the column bits and l tells which bytes in a QWORD will be affected.

When address 0x07FFFFF8 is accessed, a 64 MB SIMM will decode all row and column bits so the destination memory cells will be at row=0xFFF,col=0xFFF. On the contrary, a 1 MB SIMM will only decode 9 row and 9 column bits so the destination cells will be at row=0x1FF,col=0x1FF. A test pattern written at offsets 0x07FFFFF8 can be read back at any address higher than 1MB causing all 9 row and 9 column bits to be set. Thus finding the first occurence of the test pattern as described in setp 5 will give the actual size of the installed SIMM.

That's how a 64 MB of RAM is sized:

Write test pattern to  0x07FFFFF8 --> Row bits: 0xFFF, Column bits: 0xFFF
Read test pattern from 0x07DFFFF8 --> Row bits: 0xFBF, Column bits: 0xFFF

The first address the test pattern can be read back at is 0x07FFFFF8 so the amount of installed RAM is 128 MB (64 MB + 64 MB).

That's how a 8 MB of RAM is sized:

Write test pattern to  0x07FFFFF8 --> Row bits: 0x3FF, Column bits: 0x3FF
...
Read test pattern from 0x007ffff8 --> Row bits: 0x3FF, Column bits: 0x3FF

The first address the test pattern can be read back at is 0x007FFFF8 so the amount of installed RAM is 8 MB (4MB + 4MB).

Now the last example for 2 MB RAM:

Write test pattern to  0x07FFFFF8 --> Row bits: 0x1FF, Column bits: 0x1FF
Read test pattern from 0x07DFFFF8 --> Row bits: 0x1FF, Column bits: 0x1FF
...
Read test pattern from 0x001FFFF8 --> Row bits: 0x1FF, Column bits: 0x1FF

The first address the test pattern can be read back at is 0x001FFFF8 so the amount of installed RAM is 2 MB (1 MB + 1 MB).